Watt
Watt Definition
Watt is the unit of power (symbol: W ).
The watt unit is named after James Watt, the inventor of the steam engine.
One watt is defined as the energy consumption rate of one joule per second.
1W = 1J / 1s
One watt is also defined as the current flow of one ampere with voltage of one volt.
1W = 1V × 1A
Table of unit prefixes of watt
| Name | Symbol | Conversion | Example |
| picowatt | pW | 1pW = 10-12 W | P = 10 pW |
| nanowatt | nW | 1nW = 10-9 W | P = 10 nW |
| microwatt | μW | 1μW = 10-6 W | P = 10 μW |
| milliwatt | mW | 1mW = 10-3 W | P = 10 mW |
| watt | W | – | P = 10 W |
| kilowatt | kW | 1kW = 103 W | P = 2 kW |
| megawatt | MW | 1MW = 106 W | P = 5 MW |
| gigawatt | GW | 1GW = 109 W | P = 5 GW |
How to convert watts to kilowatts
The power P in kilowatts (kW) is equal to the power P in watts (W) divided by 1000:
P(kW) = P(W) / 1000
How to convert watts to milliwatts
The power P in milliwatts (mW) is equal to the power P in watts (W) times 1000:
P(mW) = P(W) x 1000
How to convert watts to dBm
The power P in decibel-milliwatts (dBm) is equal to 10 times base 10 logarithm of the power P in milliwatts (mW) divided by 1 milliwatt:
P(dBm) = 10 · log10( P(mW) / 1mW )
How to convert watts to amps
The current I in ampers (A) is equal to the power P in watts (W) divided by the voltage V in volts (V):
I(A) = P(W) / V(V)
How to convert watts to volts
The voltage V in volts (V) is equal to the power P in watts (W) divided by the current I in ampers (A):
V(V) = P(W) / I(A)
How to convert watts to ohms
R(Ω) = P(W) / I(A)2
R(Ω) = V(V)2 / P(W)
How to convert watts to btu/hr
P(BTU/hr) = 3.412142 · P(W)
How to convert watts to joules
E(J) = P(W) · t(s)
How to convert watts to horsepower
P(HP) = P(W) / 746
How to convert watts to kVA
The real power P in watts (W) is equal to 1000 times the apparent power S in kilo-volt-amperes (kVA) times the power factor (PF) or cosine of the phase angle φ:
P(W) = 1000 · S(kVA) · PF = 1000 · S(kVA) · cos φ
How to convert watts to VA
The real power P in watts (W) is equal to the apparent power S in volt-amperes (VA) times the power factor (PF) or cosine of the phase angle φ:
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